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Answer :

`6.7xx10^(-20)N` Solution :

First find the intermolecular distance. The mass of one cubic meter of water is `10^(3)` kg, a kilomole of water (18kg) contains `6.0 xx 10^(28)` molecules. Therefore one cubic meter of water contains `N=` <br> `=6.0xx10^(26) xx10^(3)//18 = 3.3 xx 10^(28)` molecules. Then the distance between the water molecules is <br> `d= root(3) (N) = root(3)(3.0xx10^(-20)) = 3.1 xx 10^(-10)m` <br> The force of interaction is <br> `F ~~ (6p_(e )^(2))/(4pi epsilon_(0)d^(3)) = 6.7 xx 10^(-20)N`